Answer:The graph is shown below.Step-by-step explanation:Given:[tex]y=-x+6\\8x-4y=-16[/tex]In order to graph these two lines, we find their x and y intercepts.The x intercept of [tex]y=-x+6[/tex] is at [tex]y=0[/tex]. So,[tex]0=-x+6\\x=6[/tex]Therefore, x intercept is at [tex](6,0)[/tex]The y intercept of [tex]y=-x+6[/tex] is at [tex]x=0[/tex]. So,[tex]y=0+6\\y=6[/tex]Therefore, y intercept is at [tex](0,6)[/tex]Now, similarly, we find the x and y intercepts of the other line.The x intercept of [tex]8x-4y=-16[/tex] is at [tex]y=0[/tex]. So,[tex]8x-4(0)=-16\\8x=-16\\x=\frac{-16}{8}=x=-2[/tex]Therefore, x intercept is at [tex](-2,0)[/tex]The y intercept of [tex]8x-4y=-16[/tex] is at [tex]x=0[/tex]. So,[tex]8(0)-4y=-16\\-4y=-16\\y=frac{-16}{-4}=y=4[/tex]Therefore, y intercept is at [tex](0,4)[/tex]Now, we plot these pair of points on a graph and then join the pairs of lines.The graph is shown below.