A stack of $5 and $20 bills was counted by the treasurer of an orginization. The total value of the money was $1710 and there were 47 more $5 bills than $20 bills. Find the number of each type bill

Answer:There are 106 $5 bills and 59 $20 bills.Step-by-step explanation:1. Let us call the number of $5 dollar bills x and the number of $20 bills y.The problem states that the total value of the money was $1710. This means that the total value of the $5 and $20 bills together is $1710. We can write this as:5x + 20y = 1710We are also given that there were 47 more $5 bills than $20 bills. We can write this as:x = y + 472. Thus, we have two simultaneous equations:(1) 5x + 20y = 1710(2) x = y + 473. Our aim is now to solve for x and y to find the number of each type of bill.Now there are many different methods of solving from this point onwards, however I personally would substitute x = y + 47 into equation (1), simply because this method does not require any extra rearranging.I would also simplify equation (1) before substituting to make calculations easier (especially in the case you are not using a calculator) - note however that this isn't compulsory and you would still get the same answer without simplification.Thus, simplifying we get:5x + 20y = 1710x + 4y = 342 (Divide both sides by 5)Now, substituting in x = y + 47, we get:x + 4y = 342(y + 47) + 4y = 342 (Substitute x for y + 47)5y + 47 = 342 (y + 4y = 5y)5y = 295 (Subtract 47 from both sides)y = 59 (Divide both sides by 5)Now that we know that y = 59, we can substitute this back into x = y + 47 to solve for x:x = 59 + 47 x = 1064. Thus, x = 106 and y = 59. This means that there are 106 $5 bills and 59 $20 bills.The key to this problem is to recognise the need to set up a set of simultaneous equations and then solve for the respective variables.Hope that helped but if you have any further questions please feel free to comment below :)